Example Question - distributing coefficients
Here are examples of questions we've helped users solve.
Solving a Linear Equation
To solve the equation \( y + 6 = 5(x - 7) \), we shall first expand the right side of the equation by distributing the 5 into the parentheses: \[ y + 6 = 5x - 35 \] Next, to solve for \( y \), we want to isolate \( y \) on one side of the equation. We can do this by subtracting 6 from both sides of the equation: \[ y = 5x - 35 - 6 \] \[ y = 5x - 41 \] Now the equation is solved for \( y \) in terms of \( x \). So the final expression is \( y = 5x - 41 \).
Solving Linear Equation for y
The equation provided in the image is: \(y - 1 = -3(x - 5)\) To solve this equation for y, we'll start by distributing the -3 across the (x - 5): \(y - 1 = -3x + 15\) Now, let's isolate y by adding 1 to both sides of the equation: \(y = -3x + 15 + 1\) \(y = -3x + 16\) The equation is now solved for y in terms of x. The final equation is: \(y = -3x + 16\)
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