<p>\lim_{{x \to -1}} (x^3 - 3x^2 - 2x + 1)</p> <p>\text{Para calcular el límite, sustituimos } x = -1 \text{ en la polinomio.}</p> <p>(-1)^3 - 3(-1)^2 - 2(-1) + 1</p> <p>= -1 - 3(1) + 2 + 1</p> <p>= -1 - 3 + 2 + 1</p> <p>= -1</p>
The image displays a math question with two sub-questions. Part a) is already solved in the image, where the given cubic function (x^3 - 6x^2 + 11x - 6) is factorized into (x - 1)(x - 2)(x - 3). For part b), we need to determine the x-intercepts of the cubic function. The x-intercepts of a function occur where the function equals zero. Since we have the factorized form of the cubic function, the x-intercepts can be found by setting each factor equal to zero and solving for x. Setting the factors equal to zero gives us: 1. x - 1 = 0, solving for x gives x = 1 2. x - 2 = 0, solving for x gives x = 2 3. x - 3 = 0, solving for x gives x = 3 Therefore, the x-intercepts are x = 1, x = 2, and x = 3. To sketch the graph, you would plot these x-intercepts on a coordinate axis. The cubic function is positive to the right of x = 3, negative between x = 2 and x = 3, positive between x = 1 and x = 2, and negative to the left of x = 1. The overall shape of the graph is an S-curve, with the ends of the curve heading upwards to the right and downwards to the left, considering it is a positive cubic polynomial. The turning points of the function will be between the x-intercepts, but without additional information, we cannot accurately determine their locations—just that they will be somewhere between the x-intercepts we have found.
Email: camtutor.ai@gmail.com