Example Question - converting mixed numbers
Here are examples of questions we've helped users solve.
Mathematical Operation with Millions
It seems you're asking for help with a mathematical operation that is written in a non-English language. The word "juta" suggests that the problem is likely written in Bahasa Indonesia or a similar language, where "juta" means "million." Therefore, "4.37 juta" translates to "4.37 million." The problem to solve is: \(9 \frac{1}{2} million - 4.37 million + 1,260,700\) Let's convert the mixed number to an improper fraction to deal with the millions first: \(9 \frac{1}{2} = 9 + \frac{1}{2} = 18/2 + 1/2 = 19/2\) Now, we can convert this into millions: \(19/2 \times 1,000,000 = 9,500,000\) Now, let's perform the operations: \(9,500,000 - 4,370,000 + 1,260,700\) \(= 9,500,000 - 4,370,000 = 5,130,000\) Then add the remaining number: \(5,130,000 + 1,260,700 = 6,390,700\) The answer is 6,390,700.
Adding and Converting Mixed Numbers
To solve this problem, we need to add the two amounts of newspapers collected by the two sections of Payapa School: First, let's convert the mixed numbers to improper fractions so that we can add them easily. For 18 2/5, we have: \( 18 + \frac{2}{5} = \frac{18 \times 5}{5} + \frac{2}{5} = \frac{90}{5} + \frac{2}{5} = \frac{92}{5} \) For 22 1/2, we have: \( 22 + \frac{1}{2} = \frac{22 \times 2}{2} + \frac{1}{2} = \frac{44}{2} + \frac{1}{2} = \frac{45}{2} \) Now, we need to add these two improper fractions: \( \frac{92}{5} + \frac{45}{2} \) To add them, we need a common denominator, which for 2 and 5 is 10. We need to convert each fraction to have this common denominator: \( \frac{92}{5} = \frac{92 \times 2}{5 \times 2} = \frac{184}{10} \) \( \frac{45}{2} = \frac{45 \times 5}{2 \times 5} = \frac{225}{10} \) Now we can add the two fractions: \( \frac{184}{10} + \frac{225}{10} = \frac{184+225}{10} = \frac{409}{10} \) Now, we convert this improper fraction back to a mixed number: \( \frac{409}{10} = 40 + \frac{9}{10} = 40 \frac{9}{10} \) The correct answer is C) \( 40 \frac{9}{10} \) kg.
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