Example Question - converting equation

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Converting Equation to Slope-Intercept Form and Graphing

The equation provided in the image appears to be in the form: \[ y + 6 = -\frac{3}{4}(x + 3) \] To graph this line, we need to bring it into slope-intercept form, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. We need to isolate \( y \) on one side of the equation: \[ y = -\frac{3}{4}(x + 3) - 6 \] To get rid of the parentheses, distribute \( -\frac{3}{4} \): \[ y = -\frac{3}{4}x - \frac{3}{4} \cdot 3 - 6 \] Calculating \( -\frac{3}{4} \cdot 3 \): \[ y = -\frac{3}{4}x - \frac{9}{4} - 6 \] We can convert 6 into fraction form to combine it with \( -\frac{9}{4} \): \[ -6 = -\frac{24}{4} \] So now we have: \[ y = -\frac{3}{4}x - \frac{9}{4} - \frac{24}{4} \] Combine the fractions: \[ y = -\frac{3}{4}x - \frac{33}{4} \] Now the equation is in slope-intercept form, where the slope \( m \) is \( -\frac{3}{4} \) and the y-intercept \( b \) is \( -\frac{33}{4} \). To graph this line: - Start by plotting the y-intercept at \( 0, -\frac{33}{4} \) (or if you prefer a decimal, approximately \( 0, -8.25 \)). - From the y-intercept, use the slope to determine the direction and steepness of the line. The slope \( -\frac{3}{4} \) means that for every 4 units you move to the right (positive direction along the x-axis), you move 3 units down (negative direction along the y-axis), because the slope is negative. - Plot another point using the slope from the y-intercept and then draw the line through both points extending it across the graph.

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