Example Question - completing ordered pairs
Here are examples of questions we've helped users solve.
Completing Ordered Pairs for a Linear Equation
The given equation is: y = (4/5)x + 1 We need to complete the given ordered pairs for x values -5, 0, and 5. For x = -5: y = (4/5)(-5) + 1 y = -4 + 1 y = -3 So the ordered pair is (-5, -3). For x = 0: y = (4/5)(0) + 1 y = 0 + 1 y = 1 So the ordered pair is (0, 1). For x = 5: y = (4/5)(5) + 1 y = 4 + 1 y = 5 So the ordered pair is (5, 5). To graph the solution set, you can take any two of the completed ordered pairs and plot them on the coordinate plane. Then draw a straight line through those points, which represents the equation y = (4/5)x + 1.
Completing Ordered Pairs and Graphing Linear Equations
The image shows a linear equation \( y = -\frac{2}{5}x+1 \) and we are asked to complete the given ordered pairs (0, _), (5, _), and (10, _). Also, we're supposed to use two of the ordered pairs to graph the solution set for the equation. To find the missing y-values for each x-value, we'll substitute the x-values into the equation. 1. When x = 0: \( y = -\frac{2}{5}(0) + 1 \) \( y = 0 + 1 \) \( y = 1 \) So the ordered pair is (0, 1). 2. When x = 5: \( y = -\frac{2}{5}(5) + 1 \) Because \( \frac{2}{5} \times 5 = 2 \), we have: \( y = -2 + 1 \) \( y = -1 \) So the ordered pair is (5, -1). 3. When x = 10: \( y = -\frac{2}{5}(10) + 1 \) Because \( \frac{2}{5} \times 10 = 4 \), we have: \( y = -4 + 1 \) \( y = -3 \) So the ordered pair is (10, -3). To graph these points, you would plot (0, 1), (5, -1), (10, -3) on a coordinate plane and draw a straight line through these points, which would represent the solution set for the equation \( y = -\frac{2}{5}x+1 \).
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