Example Question - bus journey

Calculating Total Distance and Average Speed of a Bus Journey

<p>Let \( d_1 \) be the distance covered in the first 2 hours, and \( d_2 \) be the distance covered in the next 4 hours.</p> <p>Given \( d_1 = 125 \) km and \( d_2 = 240 \) km.</p> <p>The total distance \( D \) covered by the bus is: \( D = d_1 + d_2 \).</p> <p>\( D = 125 \) km \( + 240 \) km.</p> <p>\( D = 365 \) km.</p> <p>Let \( t_1 \) be the time spent during the first part of the journey, and \( t_2 \) be the time spent during the second part.</p> <p>Given \( t_1 = 2 \) hours and \( t_2 = 4 \) hours.</p> <p>The total time \( T \) spent is: \( T = t_1 + t_2 \).</p> <p>\( T = 2 \) hours \( + 4 \) hours.</p> <p>\( T = 6 \) hours.</p> <p>The average speed \( V \) of the bus is calculated as \( V = \frac{D}{T} \).</p> <p>\( V = \frac{365 \text{ km}}{6 \text{ hours}} \).</p> <p>\( V \approx 60.83 \) km/hour.</p>