Example Question - area formula
Here are examples of questions we've helped users solve.
Calculating Area of a Rectangle with Given Dimensions
The image shows a worksheet with a rectangle that is divided into units to help calculate its area. The rectangle's dimensions are labeled in parts. One side is labeled as "2 units" and the other side is partially labeled with "2 units" plus an additional half unit (noted as "1/2 unit"). To find the missing information and calculate the area, we will add the lengths of the sides together. The length is 2 units plus an additional half unit, which gives us 2.5 units. The width, clearly given, is 2 units. Now that we have both dimensions of the rectangle, we can calculate the area by multiplying the length by the width. The length of Emma's rectangle is 2.5 units, and the width is 2 units. Area = length × width Area = 2.5 units × 2 units Area = 5 square units So, the area of Emma's rectangle is 5 square units.
Calculating Area of Composite Shape
To find the area of the shape in the image, the shape can be broken down into rectangular parts. With the given dimensions, we can configure two rectangles: 1. The first rectangle or the larger part has a length of 15 meters. We need to find the width of this part. By analyzing the dimensions given for the smaller parts, we can see that the overall width must be 8 meters (since one side is 8 meters and the width is consistent across that length). 2. The second rectangle has a length that is the difference between 15 meters and 5 meters (the length of the overlap), which is 10 meters. It has a width of 5 meters. Once we have identified these two rectangles, we can calculate their areas and sum them up: Area of larger rectangle: \(15 m \times 8 m = 120 m^2\) Area of smaller rectangle: \(10 m \times 5 m = 50 m^2\) Adding these two areas together: Total area = \(120 m^2 + 50 m^2 = 170 m^2\) Therefore, the area of the given shape is 170 square meters.
Calculating Area of an Irregular Figure using Rectangles
To find the area of the irregular figure, we can divide the figure into two rectangles, label them A and B as in the image, and then calculate the area for each one before summing them up. The given dimensions for Rectangle A are 6m (height) and 9m (width). The area of Rectangle A = height * width = 6m * 9m = 54m² Rectangle B overlaps with Rectangle A, but from the image, we can deduce that Rectangle B extends beyond Rectangle A by 6 m (since the height of A is 6 m, and they share a common width segment). The total width of Rectangle B is given as 18 m. Therefore, to avoid counting the overlapped area twice, we calculate the area of the extension of Rectangle B. The width of the extension of Rectangle B = total width - width of Rectangle A = 18m - 9m = 9m Using the height of Rectangle A as the height of Rectangle B (since the heights are the same): The area of the extension of Rectangle B = height * extended width = 6m * 9m = 54m² Finally, we add the areas of Rectangle A and the extension of Rectangle B together to find the total area of the irregular shape: Total area = area of A + area of B's extension = 54m² + 54m² = 108m² So, the area of the irregular figure is 108 square meters.
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