The given equation is an absolute value equation. Recall that if |x| = a, then x can either be a or -a. Let's apply this property to find all values of c. We have |c - 20| = 45. This leads to two possible cases: 1. c - 20 = 45 2. c - 20 = -45 Solving both cases: For case 1: c - 20 = 45 c = 45 + 20 c = 65 For case 2: c - 20 = -45 c = -45 + 20 c = -25 Thus, the two solutions for c are c = 65 and c = -25.
The given equation is |x - 1| = 8. To solve this equation for x, we need to consider both cases for the absolute value: Case 1: x - 1 is positive or zero. Then we have x - 1 = 8, which yields x = 8 + 1 = 9. Case 2: x - 1 is negative. Then we have -(x - 1) = 8, which simplifies to -x + 1 = 8 and then -x = 8 - 1 which gives us x = -7. So, the two possible values for x are 9 and -7. The question asks for "a possible value of x - 1". So we have to subtract 1 from each of our possible values for x: For x = 9, the value of x - 1 is 9 - 1 = 8. For x = -7, the value of x - 1 is -7 - 1 = -8. The value that matches one of the given answer choices is -8, which is option A.
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