Question - Physics Problem: Stopping a Car on a Wet Road
Solution:
The image contains a physics problem written in Italian. It describes a car with good pneumatics on a wet road that is able to brake with a constant deceleration of 4.92 m/s². There are two questions (Va) and (Vb) being asked based on this scenario:(Va) How much time does it take to stop when the initial velocity is 24.6 m/s?(Vb) How much space is needed to stop?Let's solve each question one at a time.For (Va): Time to stop (t)We can use the formula for deceleration (a) to find the time (t) it takes for the car to come to a stop with an initial velocity (u):v = u + atSince the final velocity (v) is 0 when the car stops, and we have the values for u and a, we can rearrange the formula to solve for t:0 = 24.6 m/s + (-4.92 m/s²)t-24.6 m/s = -4.92 m/s²tt = 24.6 m/s / 4.92 m/s²t = 5 secondsFor (Vb): Space needed to stop (d)We can use the formula that relates initial velocity, final velocity, deceleration, and distance:v² = u² + 2adAgain, the final velocity (v) is 0, and we have the other values:0 = (24.6 m/s)² + 2*(-4.92 m/s²)d0 = 605.16 m²/s² - 9.84 m/s²*d9.84 m/s²*d = 605.16 m²/s²d = 605.16 m²/s² / 9.84 m/s²d = 61.5 metersSo, the answers are:(Va) The time it takes for the car to come to a stop is 5 seconds.(Vb) The space needed for the car to stop is 61.5 meters.
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