Question - Calculation of Pressure Exerted by a Tourist on Snow

The pressure \( P \) exerted by an object is given by the formula \( P = \frac{F}{A} \), where \( F \) is the force and \( A \) is the area over which the force is distributed.

Here, the gravitational force \( F \) exerted by the tourist is equivalent to their weight, which can be calculated by the mass \( m \) times the gravitational acceleration \( g \), \( F = m \cdot g \).

The tourist's mass \( m \) is \( 60 \) kg, and the gravitational acceleration \( g \) is given as \( 10 \) N/kg. Thus:

\[ F = m \cdot g = 60 \, \text{kg} \cdot 10 \, \text{N/kg} = 600 \, \text{N} \]

The total area \( A \) of the shoes in contact with the snow is \( 0.6 \) m\(^2\).

So the pressure \( P \) is:

\[ P = \frac{F}{A} = \frac{600 \, \text{N}}{0.6 \, \text{m}^2} = 1000 \, \text{Pa} \]

Therefore, the answer is \( D. 1000 \) Pa.